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A rectangular tank measuring 50 cm by 50 cm by 42 cm was 2/3 filled with water. when a stone was placed in the tank the tank became 3/4 full.(a) Find the capacity of the tank in cubic centimeters.(b) Find the volume of the stone.(I already found the answer to (a) its 105,000 I just need help with finding the volume of the stone.)

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The rectangular tank has the following dimensions: 50x50x42cm, its volume can be determined as follows:


\begin{gathered} V=w\cdot l\cdot h \\ V=50\cdot50\cdot42 \\ V=105000\operatorname{cm}^3 \end{gathered}

To determine the volume of the stone, you have to calculate the amount of water that was on the tank before and after the stone was placed there.

Before the stone was placed, the tank was 2/3 full, to determine the amount this fraction represents you have to multiply the volume of the tank by 2/3


105000\cdot(2)/(3)=70000\operatorname{cm}^3

Before the stone was placed, the tank had 70000cm³ of water.

After the stone was placed, the tank was 3/4 full, to determine how much it represents, you have to multiply the volume of the tank by 3/4:


105000\cdot(3)/(4)=78750\operatorname{cm}^3

The volume of the stone is equal to the difference of the volume on the tank after the stone was placed and the volume of the tank before the stone was placed:


\begin{gathered} V_{\text{stone}}=V_{\text{after}}-V_{\text{before}} \\ V_{\text{stone}}=78750-70000 \\ V_{\text{stone}}=8750\operatorname{cm}^3 \end{gathered}

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