Question

Solving systems. x-y=2. y=4-2x

Answer 1

We have the system of equations:

`\begin{gathered} x-y=2 \\ y=4-2x \end{gathered}`

We can solve by substitution, using the information already given by the second equation.

We can replace y in the first equation and solve for x:

`\begin{gathered} x-y=2 \\ x-(4-2x)=2 \\ x-4+2x=2 \\ x+2x=2+4 \\ 3x=6 \\ x=(6)/(3) \\ x=2 \end{gathered}`

Then, we can find y using the second equation as:

`y=4-2x=4-2\cdot2=4-4=0`

Answer: x=2 and y=0