Question

the position from its starting point of a small plane preparing for takeoff is given by x(t)=1.64t^2 meters…

Answer 1

Given:

The position of the small plane is given by,

`x(t)=1.64t^2`

Step-by-step explanation:

The accelration of plane can be obtained by double derivative of the position function.

Determine the double derivative of the position function.

`\begin{gathered} (d^2)/(dt^2)x(t)=(d^2)/(dt^2)(1.64t^2) \\ a(t)=1.64\cdot(d)/(dt)(2t) \\ =3.28\cdot1 \\ =3.28 \end{gathered}`

So acceleration of the small plane is 3.28 m/s^2

Answer: 3.28