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A 58 V AC voltage source is connected across a 3.7 H inductor. What is the current through the inductor if the frequency is 63 Hz?

1 Answer

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We will have the following:

First:


x_l=2\pi(63Hz)(3.7H)\Rightarrow x_l=466.2\pi\Omega

Then:


\begin{gathered} I=(58V)/(466.2\pi\Omega)\Rightarrow I=0.03960097254...A \\ \\ \Rightarrow I\approx0.04A \end{gathered}

So, the current is approximately 0.04 A.

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