Question

Hello can someone please tell me if i did this correctlyCS2 + 3 O2 ➡️ CO2 + 2 SO2There are 20 grams of CS2 and 10grams of O2. Determine the limiting and excess reactant

Answer 1

O2 will be the limiting reactant while CS2 will be the excess reactant

Explanations:

Given the reaction between CS2 and oxygen expressed as:

`CS_2+3O_2\rightarrow CO_2+2SO_2`

Given the following pramters

Mass of CS2 = 20grams

Mass of O2 = 10grams

Determine the mole of CS2

`\begin{gathered} mole=\frac{mass}{molar\text{ mass}} \\ mole\text{ of CS}_2=(20)/(76.139) \\ mole\text{ of CS}_2=0.2627mole \end{gathered}`

Determine the mole of oxygen

`\begin{gathered} mole\text{ of O}_2=(10)/(2(16)) \\ mole\text{ of O}_2=(10)/(32)=0.3125moles \\ \end{gathered}`

Since there are 3 atoms of oxygen, 1 atom will have:

`1\text{ atom of }O_2=(0.3125)/(3)=0.1042mole`

Since the mole of oxygen is less than the mole ofCS2, hence O2 will b the limiting reactant while CS2 will be the excess reactant