Answers:
a) midpoint: (1, 4)
b) slope of PQ: 1/3
c) length of PQ: √40
d) equation of perpendicular bisector of PQ:
Step-by-step explanation:
The given points are P(4, 5) and Q(-2, 3)
Part a)
The midpoint of two points (x1, y1) and (x2, y2) can be calculated as
![((x_1+x_2)/(2),(y_1+y_2)/(2))](https://img.qammunity.org/2023/formulas/mathematics/college/b6ezm84zxxqzwlktnyn6xpt1axi8omhbm3.png)
So, replacing (x1, y1) = P(4, 5) and (x2, y2) = Q(-2, 3), we get:
![((4+(-2))/(2),(5+3)/(2))=((2)/(2),(8)/(2))=(1,4)](https://img.qammunity.org/2023/formulas/mathematics/college/u3rpfigtaudk21so3sx7qqmohteg3oa8i5.png)
Then, the midpoint of PQ is (1, 4)
Part b)
The slope of a segment that passes through points (x1, y1) and (x2, y2) can be calculated as
![\text{slope}=(y_2-y_1)/(x_2-x_1)](https://img.qammunity.org/2023/formulas/mathematics/college/x8v52dcr18u40wxqmdrkiv958nucq58v09.png)
Replacing (x1, y1) = P(4, 5) and (x2, y2) = Q(-2, 3), we get:
![\text{slope}=(3-5)/(-2-4)=(-2)/(-6)=(1)/(3)](https://img.qammunity.org/2023/formulas/mathematics/college/q1vvaelx5khkleir9r279vta52989fnnid.png)
So, the slope is 1/3
Part c)
The length of a segment that goes from (x1, y1) to (x2, y2) is calculated as
![\sqrt[]{(x_2-x_1)^2+(y_2-y_1)^2}](https://img.qammunity.org/2023/formulas/mathematics/college/s91s233vun4sfi433g8exahmp5kohnyvcn.png)
Replacing (x1, y1) = P(4, 5) and (x2, y2) = Q(-2, 3), we get:
![\begin{gathered} \sqrt[]{(-2-4)^2+(3-5)^2} \\ \sqrt[]{(-6_{})^2+(-2)^2} \\ \sqrt[]{36+4} \\ \sqrt[]{40} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/p4thnhebbk7748q3luwc9opbxqtw800dqn.png)
Therefore, the length of PQ is √40.
Part d)
The perpendicular bisector of PQ is a line that divides the segment into two equal and forms a 90 degrees angle with the segment.
First, we need to calculate the slope of the line. Taking into account that the slope of perpendicular lines multiply to -1, we get that the slope of the perpendicular bisector is
![\begin{gathered} m\cdot(1)/(3)=-1 \\ m\cdot(1)/(3)\cdot3=-1\cdot3 \\ m=-3 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/euzyvipqteje2ggvr4fzvk0q1ueqchbvwa.png)
Additionally, the perpendicular bisector will pass through the midpoint of PQ, so it will pass through (1, 4).
Now, the equation of a line with slope m= -3 that passes through the point (x1, y1) = (1, 4) is
![\begin{gathered} y-y_1=m(x-x_1) \\ y-4=-3(x-1) \\ y-4=-3x-3(-1) \\ y-4=-3x+3 \\ y-4+4--3x_{}+3+4 \\ y=-3x+7 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/lrfe82nyxbyso0aop6dzufpzst0tie8hr9.png)
Therefore, the equation of the perpendicular bisector is y = -3x + 7.