The initial expression is
![\sqrt[]{(16x^4y^8)/(5z)}](https://img.qammunity.org/2023/formulas/mathematics/college/unclmfmvcev8u5757owdd0dsvfxquafm68.png)
This can be simplified as shown below
![\begin{gathered} \sqrt[]{(16x^4y^8)/(5z)}=\frac{\sqrt[]{16x^4y^8}}{\sqrt[]{5z}} \\ =\frac{\sqrt[]{16}\sqrt[]{x^4}\sqrt[]{y^8_{}}}{_{}\sqrt[]{5}\sqrt[]{z}} \\ =\frac{4x^2y^4}{\sqrt[]{5}\sqrt[]{z}} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/g8eoxc1v5vp88jrsdpgdzg4dtxofrs8o3b.png)
Now, we need to rationalize the denominator. First, we need to multiply the simplified expression by 1
![\begin{gathered} \Rightarrow\sqrt[]{(16x^4y^8)/(5z)}=\frac{4x^2y^4_{}}{\sqrt[]{5z}}\cdot1=\frac{4x^2y^4_{}}{\sqrt[]{5z}}\cdot\frac{\sqrt[]{5z}}{\sqrt[]{5z}}=\frac{4x^2y^4\sqrt[]{5z}}{5z} \\ \Rightarrow\sqrt[]{(16x^4y^8)/(5z)}=\frac{4x^2y^4\sqrt[]{5z}}{5z} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/3jnx2m7fq6wdndkdfwtqdxpjiohibdz0b5.png)
We can modify how the final expression looks like, but this is the answer.
The answer is (4x^2y^4sqrt(5z))/5z