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Solve for x.x^2 + 6x + 9 = 12x= -3+2V3x = -3+4V3x= -9 + 4V3x=-9 + 2V3
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Solve for x.x^2 + 6x + 9 = 12x= -3+2V3x = -3+4V3x= -9 + 4V3x=-9 + 2V3

User Andlabs
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1 Answer

1 vote

1) Solving this quadratic equation by the Resolutive formula, we have:


\begin{gathered} x^2+6x\text{ +9=12} \\ x^2+6x-12+9=0 \\ x^2+6x-4=0 \\ \Delta=b^2-4ac=6^2-4(1)(-4)=36+16=52 \\ x=\frac{-6\pm\sqrt[]{52}}{2} \\ x_1=-3+\sqrt[]{13} \\ x_2=-3-\sqrt[]{13} \\ S=\mleft\lbrace-3-\sqrt[]{13},-3+\sqrt[]{13}\mright\rbrace \end{gathered}

User Lenkite
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