We know that Jack has narrowed down his selection to a total of:
![7+7+4+4=22](https://img.qammunity.org/2023/formulas/mathematics/high-school/zjnkj1iw1wbptc8w7o6q6j6dghgybb2qwy.png)
items.
Since he wants all the cheeses and he wants to use the express lane he needs to select a total of:
![15-4=11](https://img.qammunity.org/2023/formulas/mathematics/high-school/44jh7ebqrnmh97ez5wsyshujnglcop7eoc.png)
more items.
From the total number of items he will select:
![22-4=18](https://img.qammunity.org/2023/formulas/mathematics/high-school/6m8hi9qqu15c2r457reybjt5x5wzghztv5.png)
items.
Then he needs to select 11 item from 18 possible items. To determine in how many ways can do this we can use a combination, a combination is given by:
![C(n,r)=(n!)/(r!(n-r)!)](https://img.qammunity.org/2023/formulas/mathematics/high-school/6w59b5bnx99xew2xcl88ekb8s5usdpz7zk.png)
Then we have:
![C(18,11)=(18!)/(11!(18-11)!)=31824](https://img.qammunity.org/2023/formulas/mathematics/high-school/pl5dmn31qwvwsmtk8w6spuhflome4lh5li.png)
Therefore, there are 31824 ways Jack can choose 15 items if he wants all the cheeses