Solution
We are given 6 numbers, we want to find how many four digits different number that can be formed
Note: All the six numbers are available to occupy the first space of the 4 digit number. There would just be 5 numbers availabe for the second space and 4 numbers for the third and 3 for the last.
Therefore, the number of different combinations is
![6*5*4*3=360](https://img.qammunity.org/2023/formulas/mathematics/college/nf9v3hdgep2i1k046k5gtg5k51o6uy779x.png)
The answer is
![360](https://img.qammunity.org/2023/formulas/mathematics/college/qydqov72lkhos5040k84dtgi6hcjtrg9ox.png)