Problem
We have the following function given
p(t)= -12 t ^2 +480 t +30
Solution
In order to maximize this function we need to take the derivate and we got:
p'(t)= -24t +480
Now we need to set up the derivate equal to 0 and we got:
-24t +480=0
And solving for t we have:
t= 480/24 = 20
Then the function have a maximum at t= 20 with a value of:
p(20) = -12 (20^2) +(480*20) +30= 4830
Answer = 20