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A hammock is suspended between two trees. The curve the hammock makes can bemodelled by the equation y = 0.2x² - 0.4x - 0.6, where x and y are measured inmetres.a) Find the x interceptsb) Find the vertex.c) What is the minimum height of the hammock?

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We have the function that relates x and y expressed as:


y=0.2x^2-0.4x-0.6

a) We have to find the x-intercepts.

To do that we can use the quadratic equation:


\begin{gathered} x=(-(-0.4)\pm√((-0.4)^2-4(0.2)(-0.6)))/(2(0.2)) \\ x=(0.4\pm√(0.16+0.48))/(0.4) \\ x=(0.4\pm√(0.64))/(0.4) \\ x=(0.4\pm0.8)/(0.4) \\ x=1\pm2 \\ x_1=1-2=-1 \\ x_2=1+2=3 \end{gathered}

Then, we have x-intercepts at x = -1 and x = 3.

b) We have to find the vertex.

We can find the x-coordinate of the vertex using the linear coefficient b = -0.4 and the quadratic coefficient a = 0.2:


x_v=(-b)/(2a)=(-(-0.4))/(2(0.2))=(0.4)/(0.4)=1

It can also be calculated as the average of the x-intercepts.

Knowing the x-coordinate of the vertex, we can find the y-coordinate of teh vertex using the formula applied to x = 1:


y=0.2(1)^2-0.4(1)-0.6=0.2-0.4-0.6=-0.8

Then, the vertex is (1, -0.8).

c) The minimum height will be given by the y-coordinate of the vertex.

Relative to the horizontal axis (y = 0), the minimum height will be -0.8 meters below that level.

Answer:

a) The x-intercepts are x = -1 and x = 3.

b) The vertex is (1,-0.8)

c) The minimum height is 0.8 units below the horizontal axis.

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