140k views
5 votes
A hammock is suspended between two trees. The curve the hammock makes can bemodelled by the equation y = 0.2x² - 0.4x - 0.6, where x and y are measured inmetres.a) Find the x interceptsb) Find the vertex.c) What is the minimum height of the hammock?

1 Answer

0 votes

We have the function that relates x and y expressed as:


y=0.2x^2-0.4x-0.6

a) We have to find the x-intercepts.

To do that we can use the quadratic equation:


\begin{gathered} x=(-(-0.4)\pm√((-0.4)^2-4(0.2)(-0.6)))/(2(0.2)) \\ x=(0.4\pm√(0.16+0.48))/(0.4) \\ x=(0.4\pm√(0.64))/(0.4) \\ x=(0.4\pm0.8)/(0.4) \\ x=1\pm2 \\ x_1=1-2=-1 \\ x_2=1+2=3 \end{gathered}

Then, we have x-intercepts at x = -1 and x = 3.

b) We have to find the vertex.

We can find the x-coordinate of the vertex using the linear coefficient b = -0.4 and the quadratic coefficient a = 0.2:


x_v=(-b)/(2a)=(-(-0.4))/(2(0.2))=(0.4)/(0.4)=1

It can also be calculated as the average of the x-intercepts.

Knowing the x-coordinate of the vertex, we can find the y-coordinate of teh vertex using the formula applied to x = 1:


y=0.2(1)^2-0.4(1)-0.6=0.2-0.4-0.6=-0.8

Then, the vertex is (1, -0.8).

c) The minimum height will be given by the y-coordinate of the vertex.

Relative to the horizontal axis (y = 0), the minimum height will be -0.8 meters below that level.

Answer:

a) The x-intercepts are x = -1 and x = 3.

b) The vertex is (1,-0.8)

c) The minimum height is 0.8 units below the horizontal axis.

User RichieRock
by
6.4k points
Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.