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How to solve (2a)^2-40b a=5 b=2

User Ronin
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We are given the following expression


(2a)^2-40b

Where a = 5 and b = 2

Let us substitute the values of a and b into the above expression


\begin{gathered} (2a)^2-40b \\ (2\cdot5)^2-40\cdot2 \\ (10)^2-80 \\ (10*10)-80 \\ 100-80 \\ 20 \end{gathered}

Therefore, the result of the expression is 20.

User QuAnton
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