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A line's slope is -1. The line passes through the point (2,1). Find an equation for this line in both point-slope and slop fom. An equation for this line in point-slope form is:An equation for this line in slope-intercept form is:

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Answer

An equation for this line in point-slope form is:

y - 1 = -1 (x - 2)



An equation for this line in slope-intercept form is:​

y = -x + 3

Step-by-step explanation

The general form of the equation in point-slope form is

y - y₁ = m (x - x₁)

where

y = y-coordinate of a point on the line.

y₁ = This refers to the y-coordinate of a given point on the line

m = slope of the line.

x = x-coordinate of the point on the line whose y-coordinate is y.

x₁ = x-coordinate of the given point on the line

Slope = m = -1

Point = (x₁, y₁) = (2, 1)

x₁ = 2

y₁ = 1

y - y₁ = m (x - x₁)

y - 1 = -1 (x - 2)

We can then simplify this to obtain the equation of the line in slope-intercept form

y - 1 = -1 (x - 2)

y - 1 = -x + 2)

y = -x + 2 + 1

y = -x + 3

Hope this Helps!!!

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