Angles A, B, and C together add to 180 degrees.
We can find Angle B:

side a is opposite angle A, side b is opposite angle B.
We now have pairs for which we can solve for a side [either a or b].
We will use sin rule, which is:

Let's find a first using known and unknown pairs:

By similar process, we find b:

Angle B = 41.5 degrees
Side a = 30.36
Side b = 32.61