Question

Factor the expression
49x^5 - 63x^3

Answer 1

`7x^3(7x^2-9 )`

Explanation:

To factor, you have to find the GCF of 49 and 63 and the GCF of
`x^(5)` and
`x^3`

Factor 49: 1,7, and 49

Factor 63: 1, 3, 7, 9, 21, 63

Factor
`x^(5)`:
`x*x*x*x*x`

Factor
`x^3`:
`x*x*x`

So the GCF of 49 and 63 is 7

The GCF of
`x^(5)` and
`x^(3)` is
`x^3`

We multiply 7 by
`x^(3)` to get
`7x^3`

So now we start to factor out the GCF of
`49x^5-63x^3`

`7x^3((49x^5)/(7x^3)+ (63x^3)/(7x^3) )`

`(49)/(7) =7\\x^5-x^3=x^2`

`(63)/(7) =9\\x^3-x^3=x^0` because
`x^(0)` can't be written as an exponent we don't write
`9x^0`

When we factor we get
`7x^3(7x^2-9 )`

Answer 2

7x³(7x² - 9)

Explanation:

Hope this helps!