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ACD"E" is a translation of ACD"E". What is the translation rule? (The "A" is actually a triangle)

User Redskull
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Answer

We can see that triangle C'D'E' was obtained by translating the coordinates of the vertices of triangle CDE 10 units to the left and 11 units downwards.

Step-by-step explanation

When a coordinate A(x, y) is translated horizontally along the x-axis by a units, the new coordinates, A'(x', y') is represented as

A[(x + a), y] when the translation is by a units to the right.

A[(x - a), y] when the translation is by a units to the left.

When a coordinate A(x, y) is translated vertically along the y-axis by b units, the new coordinates, A'(x', y') is represented as

A' [x, (y + b)] when the translation is by b units upwards.

A [x, (y - b)] when the translation is by b units downwards.

When a coordinate A(x, y) is translated horizontally along the x-axis by a units and vertically along the y-axis by b units, the new coordinates, A'(x', y') is represented as

A' [(x + a), (y + b)]

A' [(x + a), (y - b)]

A' [(x - a), (y + b)]

A' [(x - a), (y - b)]

All depending on how the coordinate is moved.

For the vertices of the triangles in the question, we can take one of them, E and E' for example, and see how much E has to be moved to give E'.

We can see that E has to be moved to the left by 10 units and downwards by 11 units to give E'.

Hope this Helps!!!

User Avinash Raut
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