Answer
We can see that triangle C'D'E' was obtained by translating the coordinates of the vertices of triangle CDE 10 units to the left and 11 units downwards.
Step-by-step explanation
When a coordinate A(x, y) is translated horizontally along the x-axis by a units, the new coordinates, A'(x', y') is represented as
A[(x + a), y] when the translation is by a units to the right.
A[(x - a), y] when the translation is by a units to the left.
When a coordinate A(x, y) is translated vertically along the y-axis by b units, the new coordinates, A'(x', y') is represented as
A' [x, (y + b)] when the translation is by b units upwards.
A [x, (y - b)] when the translation is by b units downwards.
When a coordinate A(x, y) is translated horizontally along the x-axis by a units and vertically along the y-axis by b units, the new coordinates, A'(x', y') is represented as
A' [(x + a), (y + b)]
A' [(x + a), (y - b)]
A' [(x - a), (y + b)]
A' [(x - a), (y - b)]
All depending on how the coordinate is moved.
For the vertices of the triangles in the question, we can take one of them, E and E' for example, and see how much E has to be moved to give E'.
We can see that E has to be moved to the left by 10 units and downwards by 11 units to give E'.
Hope this Helps!!!