• Let n be number of student who responded = 145
• Let x be number of student who attended basketball = 22
,
• P = sample proportion = x/n = 22/145 = 0.15
,
• The 95% confidence interval forstudent who attended basketball game can be estimated as below :
[tex]\begin{gathered} P^{\text{ }}-E
Interpretation of the above : we have 95 % confidence that the population percentage of women who attended the basket ball game will lie between 0.09 and 0.21.