What is the value of f(-3) when f(x)=x^2+4x+5

asked Dec 22, 2023 186k views

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3 votes

Step-by-step explanation

Step 1

replace

when x=-3

then,

$\begin{gathered} f(x)=x^2+4x+5 \\ f(-3)=(-3)^2+4(-3)+5 \\ f(-3)=9-12+5 \\ f(-3)=2 \end{gathered}$

I hope this helps you

Rakward answered Dec 29, 2023

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