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What is the value of f(-3) when f(x)=x^2+4x+5

1 Answer

3 votes

f(-3)=2

Step-by-step explanation


f(x)=x^2+4x+5

Step 1

replace

when x=-3

then,


\begin{gathered} f(x)=x^2+4x+5 \\ f(-3)=(-3)^2+4(-3)+5 \\ f(-3)=9-12+5 \\ f(-3)=2 \end{gathered}

I hope this helps you

User Rakward
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