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Geometry or algebra 2 thanks so much its asking for cot

Geometry or algebra 2 thanks so much its asking for cot-example-1
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1 Answer

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Answer: We have to evaluate the cotangent for the given x and y coordinate points:


\begin{gathered} (x,y)=((√(3))/(4),-(√(13))/(4)) \\ \\ x=(√(3))/(4) \\ \\ y=-(√(13))/(4) \end{gathered}

The value of the cot function is:


\begin{gathered} cot(\theta)=(x)/(y) \\ \\ \therefore\rightarrow \\ \\ =(√(3))/(4)/-(√(13))/(4)=-(√(3))/(√(13))=-\sqrt{(3)/(13)} \\ \\ =-\sqrt{(3)/(13)} \end{gathered}