Answer:
• x-intercept: (-1.5, 0).
,
• y-intercept: (0, 1).
Explanation:
Given the function:
![f(x)=(2x+3)/(x^2+3)](https://img.qammunity.org/2023/formulas/mathematics/college/x7oc3ax8gqkus76y7cbh4jjc7ns7jzqizy.png)
(a)x-intercept
The x-intercept is the value of x at which f(x)=0.
When f(x)=0
![\begin{gathered} (2x+3)/(x^2+3)=0 \\ \text{ Cross multiply} \\ 2x+3=0 \\ \text{ Subtract 3 from both sides of the equation} \\ 2x+3-3=0-3 \\ 2x=-3 \\ \text{ Divide both sides of the equation by 2} \\ (2x)/(2)=-(3)/(2) \\ x=-1.5 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/9q4qemk6wezdypuoynjke52nzspxmn21d1.png)
The x-intercept is located at (-1.5, 0).
(b)y-intercept
The y-intercept is the value of f(x) at which x=0.
When x=0
![\begin{gathered} f(x)=(2x+3)/(x^2+3) \\ f(x)=(3)/(3) \\ f(x)=1 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/eyr5bjf3ry8ivcjd72lprypx1detptegb4.png)
The y-intercept is at (0, 1).
(c)Graph
The graph of f(x) is given below: