Question

How many grams would be contained in 3.49 x 10^80 molecules of H2S04?

Answer 1

There would be 5.7x10^58 grams.

Step-by-step explanation:

1st) It is necessary to convert the 3.49x10^80 molecules to moles, by using the Avogadro's number. The A vogadro's number is 6.022x10^23 particles, in this case molecules, that are contained in 1 moles of a substance:

`\begin{gathered} 6.022*10^(23)molecules-1mole \\ 3.49*10^(80)molecules-x=(3.49*10^(80)molecules*1mole)/(6.022*10^(23)molecules) \\ x=5.8*10^(56)moles \end{gathered}`

2nd) Now with the number of moles and the molar mass of H2SO4 (98g/mol) we can calculate the grams:

`\begin{gathered} 1mole-98g \\ 5.8*10^(56)moles-x=(5.8*10^(56)moles*98g)/(1mole) \\ x=5.7*10^(58)g \end{gathered}`

So, there would be 5.7x10^58 grams.