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Determine the number of degrees in the arcs?

User AleshaOleg
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First, we find angle K


\begin{gathered} m\angle K+90+56=180 \\ m\angle K=180-90-56=34 \end{gathered}

Then, we use the inscribed angle theorem


\begin{gathered} m\angle K=(1)/(2)\cdot PM \\ PM=2\cdot m\angle K=2\cdot34=68 \end{gathered}

Hence, the arc PM measures 68°.

Also, the arc MP measures 68° because it's the same arc.

If arc MT is 170°, and MP is 68°, then


PT=170-68=102

Then, we observe that arc KTP is equal to 180° because it's half the circumference. So,


\begin{gathered} KT+TP=KTP \\ KT+102=180 \\ KT=180-102=78 \end{gathered}

Hence, arc KT measures 78°.

User VirtualLogic
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