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How many moles are there in 8.46 x 10^24 molecules of sodium fluoride?

1 Answer

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Answer:

14.05moles

Explanations:

According to the Avogadro constant


1mole\text{ of NaF}=6.02*10^(23)molecule

Given the following parameter

Molecules of NaF = 8.46 x 10^24molecules

Determine the moles of NaF


\begin{gathered} moles\text{ }of\text{ NaF}=(8.46*10^(24))/(6.02*10^(23)) \\ moles\text{ of NaF}=1.405*10^(24-23) \\ moles\text{ of NaF}=1.405^*10^1 \\ moles\text{ of NaF}=14.05moles \end{gathered}

Hence the moles of NaF that are in 8.46 x 10^24 molecules of sodium fluoride is 14.05moles

User Jim Gilmartin
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