Answer:
14.05moles
Explanations:
According to the Avogadro constant
![1mole\text{ of NaF}=6.02*10^(23)molecule](https://img.qammunity.org/2023/formulas/chemistry/college/yklddl2umrgb5rceg9zj12b695iuciq1tl.png)
Given the following parameter
Molecules of NaF = 8.46 x 10^24molecules
Determine the moles of NaF
![\begin{gathered} moles\text{ }of\text{ NaF}=(8.46*10^(24))/(6.02*10^(23)) \\ moles\text{ of NaF}=1.405*10^(24-23) \\ moles\text{ of NaF}=1.405^*10^1 \\ moles\text{ of NaF}=14.05moles \end{gathered}](https://img.qammunity.org/2023/formulas/chemistry/college/j6mag2w6sjwkn21f51sk48lmieguyur0ig.png)
Hence the moles of NaF that are in 8.46 x 10^24 molecules of sodium fluoride is 14.05moles