Question

A box weighing 51.1 N is pulled horizontally until it slides uniformly over a level floor. If the applied force is 6.30 N, what is the coefficient of friction between the box and the floor?

Answer 1

Given data

*A box weighs is N = 51.1 N

*The applied force is F = 6.30 N

The formula for the coefficient of friction between the box and the floor is given as

`\mu=(F)/(N)`

Substitute the known values in the above expression as

`\begin{gathered} \mu=(6.30)/(51.1) \\ =0.123 \end{gathered}`

Hence, the coefficient of friction between the box and the floor is 0.123