Question

The first of two numbers is twice the second. Seven more than the second number is equalto 6 less than the first number. Find the numbers.

Answer 1

Let's call x to the first number ans y to the second number.

The first of two numbers is twice the second:

x = 2y

Seven more than the second number is equal to 6 less than the first number:

7 + y = x - 6

Isolating x:

7 + y + 6 = x

13 + y = x

Combining last equation with first equation:

2y = 13 + y

2y - y = 13

y = 13

Then:

x = 2*13

x = 26