140k views
2 votes
Find an equation of the line perpendicular to y = - 2x + 6 that crosses the point(-2,8). Write your equation in slope-intercept form.

User Valerie R
by
8.3k points

1 Answer

4 votes

To solve this problem, the first step is to find the slope of the line. With the given information, we know that the line is perpendicular to y=-2x+6, find the slope of the line by knowing that the product of the slopes of two perpendicular lines is -1.


\begin{gathered} m1\cdot m2=-1 \\ -2\cdot m2=-1 \\ m2=-(1)/(-2) \\ m2=(1)/(2) \end{gathered}

With this slope and the given point, use the point slope formula to find the equation of the line in slope intercept form.


\begin{gathered} y-y1=m(x-x1) \\ y-8=(1)/(2)(x-(-2)) \\ y-8=(1)/(2)(x+2) \\ y-8=(1)/(2)x+1 \\ y=(1)/(2)x+9 \end{gathered}

User Zeyad Gasser
by
8.4k points

No related questions found

Welcome to QAmmunity.org, where you can ask questions and receive answers from other members of our community.

9.4m questions

12.2m answers

Categories