Question

suppose a normal distribution has a mean of 62 and a standard deviation of4. What is the probability that a data value is between 54 and 66? Round youranswer to the nearest tenth of a percent

Answer 1

For this case we have the following info given:

`X\approx N(62,4)`

and we want to find this probability:

P(54And we can use the z score and we have:

`z=(54-62)/(4)=-2`
`z=(66-62)/(4)=1`

And we have this:

[tex]P(54And the final answer would be 81.9%