Answer:
97.73%
Explanation:
SAT scores are normally distributed with:
• Mean = 500
,
• Standard deviation = 100
We want to find out what percentage of the students who took SAT scored less than Jenna if Jenna earns 700 points.
In order to do this, we first find the z-score using the formula below:
For a raw score, X = 700:
Therefore, Jenna did better than 97.73% of students who took the SAT.