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Find the equation of a line that is parallel to the line and contains the point

Find the equation of a line that is parallel to the line and contains the point-example-1

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Lines can be written in slope-intercept form, and this form is:


y=mx+b

Where 'm' represents the slope of the line, and 'b' represents the y-intercept. The line given in the question is written in this form, with the following coefficients


\begin{cases}m=-3 \\ b=0\end{cases}

Parallel lines, have the same slope. It means, our parallel line have the following form


y=-3x+b

Now, we can just use our given point to find out the 'b' coefficient. Our point is (1, -5), making the substitution, we have


-5=-3\cdot1+b\Rightarrow-5=-3+b\Rightarrow b=-2

Our parallel line that contains the point (1, -5) is


y=-3x-2

User Robin Robinson
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