Lines can be written in slope-intercept form, and this form is:
![y=mx+b](https://img.qammunity.org/2023/formulas/mathematics/high-school/smsb8cbft03lwblmi49nf2l6jby2ofxzws.png)
Where 'm' represents the slope of the line, and 'b' represents the y-intercept. The line given in the question is written in this form, with the following coefficients
![\begin{cases}m=-3 \\ b=0\end{cases}](https://img.qammunity.org/2023/formulas/mathematics/college/e0adpyaicfyk2i3aayklos2qm5itbv5b4e.png)
Parallel lines, have the same slope. It means, our parallel line have the following form
![y=-3x+b](https://img.qammunity.org/2023/formulas/mathematics/college/4sbwu75cfh7n19kjzr6rp2h698eh3vse7u.png)
Now, we can just use our given point to find out the 'b' coefficient. Our point is (1, -5), making the substitution, we have
![-5=-3\cdot1+b\Rightarrow-5=-3+b\Rightarrow b=-2](https://img.qammunity.org/2023/formulas/mathematics/college/d43gm4cfachubi43tprmuuhaawgyvq0lm8.png)
Our parallel line that contains the point (1, -5) is
![y=-3x-2](https://img.qammunity.org/2023/formulas/mathematics/college/ngoa0ltc44pfqizl0uhfazpvuwtxhw2vxe.png)