Deejilani, this is the solution to the problem:
The information provided to us:
Mean = 28,000
S.D = 2,500
Number of tires = 2,000
Distance of cut-off (x) = 23,000
Step 1: Let's calculate the z-score, as follows:
z = (x - Mean)/Standard Deviation
z = (23,000 - 28,000)/2,500
z = -5,000/2,500
z = -2
Step 2: Now we calculate the Probability of z = -2, using the z-table, this way:
P (x < 23,000) = 0.02275
Step 3: Now we find the number of tires that are likely to wear out before 23,00 miles, as follows:
2,000 * 0.02275 = 45.5
Rounding to the next integer because tires cannnot be a decimal number: 46 tires are likely to wear out before 23,000 miles