1 Answer

Ersan J Sano · Answer 1 · 2023-05-24T03:16:58+0000

ANSWER

20 N

Step-by-step explanation

Torque produced by a force F perpendicular to a lever arm with length r is:

$\tau=F\cdot r$

In this case we have to find F, when τ = 500 N*cm and r = 25cm:

$500Ncm=F\cdot25\operatorname{cm}$

Solving for F:

$F=\frac{500Ncm}{25\operatorname{cm}}=20N$

To produce a torque of 500N*cm, a perpendicular force of 20N must be applied

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