29.5k views
5 votes
What force in newtons must be applied perpendicular to the end of a wrench handle 25 cm long to produce torque 500N *cm

User Andie
by
5.0k points

1 Answer

0 votes

ANSWER

20 N

Step-by-step explanation

Torque produced by a force F perpendicular to a lever arm with length r is:


\tau=F\cdot r

In this case we have to find F, when τ = 500 N*cm and r = 25cm:


500Ncm=F\cdot25\operatorname{cm}

Solving for F:


F=\frac{500Ncm}{25\operatorname{cm}}=20N

To produce a torque of 500N*cm, a perpendicular force of 20N must be applied

User Ersan J Sano
by
4.9k points