Question

Solve
`(1)/(2) (20 - 4a)6 - a`between 4a) and 6 is suppost to be a = like 4a)=6

Answer 1

`(1)/(4)(20-4a)=6-a`
`\begin{gathered} 5-a=6-a \\ 5-a=6-a \\ -a+a=6-5 \\ 0=1 \end{gathered}`

That is inconsistent, therefore there is no solution