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Solve (1)/(2) (20 - 4a)6 - abetween 4a) and 6 is suppost to be a = like 4a)=6
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(1)/(2) (20 - 4a)6 - abetween 4a) and 6 is suppost to be a = like 4a)=6

User Viktor Skliarov
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1 Answer

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(1)/(4)(20-4a)=6-a
\begin{gathered} 5-a=6-a \\ 5-a=6-a \\ -a+a=6-5 \\ 0=1 \end{gathered}

That is inconsistent, therefore there is no solution

User JR Smith
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