Step-by-step explanation:
For any right triangle
the relationship between the hypotenuse and the adjacent side of an angle theta is the cosine of the angle:
![\cos \theta=(b)/(a)](https://img.qammunity.org/2023/formulas/mathematics/college/r4f6cps7d6blvi2mlbi3cj79pmo6xfxito.png)
In this problem we have b = 16m and a = 25m. Therefore the cosine of x is:
![\cos x=(16m)/(25m)=0.64](https://img.qammunity.org/2023/formulas/mathematics/college/kzlffe21tqg3tycqd4ka69oovxogj46gqy.png)
Using the inverse of the cosine - "the arc whose cosine is x" - we find x:
![\begin{gathered} x=\arccos 0.64 \\ x\approx50.21º\approx0.88rad \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/nfw9wm7a1ri2yrugsyhslwg3uoxqxq8s8a.png)
Answer:
The value of the angle is x = 50.21º or x = 0.88 radians