Question

Assume that y varies inversely with x. If y= 16 when x = 0.5, find y when x = 32.y=[ ? ]

Answer 1

Given

y=16, when x = 0.5

Find

value of y when x is 32

Step-by-step explanation

`\begin{gathered} y=(k)/(x) \\ 16=(k)/(0.5) \\ k=8 \end{gathered}`

Now putting this value again in y=k/x

`\begin{gathered} y=(k)/(x) \\ y=(8)/(32)=(1)/(4)=0.25 \end{gathered}`

Final Answer

Value of y will be 0.25