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The terms of a sequence are given. Use these terms to answer the following questions. 2, 8, 14, 20, 26 Write a RECURSIVE rule & an EXPLICIT rule to represent the arithmetic sequence. Make sure to explain how you got your answer.

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The given sequence is


2,8,14,20,26

The standard Explicit formula for an arithmetic sequence is given by


a_n=a_1+(n-1)d

Where aₙ is the nth term, a₁ is the first term and d is the common difference

The common difference is basically the difference between any two consecutive terms

d = 26 - 20 = 6

d = 20 - 14 = 6

d = 14 - 8 = 6

d = 8 - 2 = 6

So the common difference is 6

The first term in the sequence is 2

So the Explicit formula for an arithmetic sequence becomes


a_n=2+(n-1)\cdot6

Now let us find the Recursive rule of this arithmetic sequence


a_n=a_(n-1)+d

Where aₙ is the nth term, aₙ₋₁ is the previous term of the nth term, and d is the common difference

We already know the common difference is 6

So the Recursive rule for an arithmetic sequence becomes


a_n=a_(n-1)+6

Therefore, the RECURSIVE rule & EXPLICIT rules are


\begin{gathered} Recursive\: Rule\colon\: \: a_n=a_(n-1)+6 \\ Explicit\: Rule\colon\: \: a_n=2_{}+(n-1)\cdot6 \end{gathered}

Let us simplify the above explicit rule


\begin{gathered} a_n=2+(n-1)\cdot6 \\ a_n=2+6n-6 \\ a_n=6n+2-6 \\ a_n=6n-4 \end{gathered}

Therefore, the above explicit rule is also valid.

User Paul Iluhin
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