Given:
The metal sheet has 5 defects per 11 square feet.
To find:
The probability that a 19 square foot metal sheet has at least 9 defects.
Step-by-step explanation:
On an average,
![\begin{gathered} λ=5*(19)/(11) \\ λ=8.64\text{ defects per 11 square feet.} \end{gathered}]()
Then, using the poison distribution,
![\begin{gathered} P\left(X≥9\right)=1−P\left(X<9\right) \\ =1−e^(-λ)\sum_{i\mathop{=}0}^8(λ^i)/(i!) \\ =1−e^(-8.64)\sum_{i\mathop{=}0}^8(8.64^i)/(i!) \\ =1-0.5039 \\ =0.49606 \\ \approx0.496 \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/college/xnmzeklr4qab9s9d5q5n7kaf1ncfte4l5s.png)
Thus, the probability that a 19 square foot metal sheet has at least 9 defects is 0.496.
Final answer:
The probability that a 19 square foot metal sheet has at least 9 defects is 0.496.