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A certain kind of sheet metal has, on average, 5 defects per 11 square feet.Assuming a Poisson distribution, find the probability that a 19 square foot metal sheet has at least 9 defects. Round your answer to three decimal places.

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Given:

The metal sheet has 5 defects per 11 square feet.

To find:

The probability that a 19 square foot metal sheet has at least 9 defects.

Step-by-step explanation:

On an average,


\begin{gathered} λ=5*(19)/(11) \\ λ=8.64\text{ defects per 11 square feet.} \end{gathered}

Then, using the poison distribution,


\begin{gathered} P\left(X≥9\right)=1−P\left(X<9\right) \\ =1−e^(-λ)\sum_{i\mathop{=}0}^8(λ^i)/(i!) \\ =1−e^(-8.64)\sum_{i\mathop{=}0}^8(8.64^i)/(i!) \\ =1-0.5039 \\ =0.49606 \\ \approx0.496 \end{gathered}

Thus, the probability that a 19 square foot metal sheet has at least 9 defects is 0.496.

Final answer:

The probability that a 19 square foot metal sheet has at least 9 defects is 0.496.

User Raul Gonzales
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