Question

A basketball player jumps for a rebound and reaches a maximum height of 1.5 m. with what speed did he jump off the floor? How long was he in the air?

Answer 1

The final speed of the player can be given as,

`v^2=u^2-2gh`

At the maximum height, the final speed of player is zero.

Plug in the known values,

`\begin{gathered} (0m/s)^2=u^2-2(9.8m/s^2)(1.5\text{ m)} \\ u^2=29.4m^2s^(-2) \\ u=5.42\text{ m/s} \end{gathered}`

Thus, the speed with which it jump off the floor is 5.42 m/s.

The time for which the player was in player is,

`t=\sqrt[]{(2h)/(g)}`

Plug in the known values,