Given the following Quadratic equation:

You can use the Quadratic formula to solve it:
![x=\frac{-b\pm\sqrt[]{b^2-4ac}}{2a}](https://img.qammunity.org/2023/formulas/mathematics/college/rxvf73usjbbwyik14knxdemoz21vfz2ufc.png)
In this case, you need to add "3x" to both sides of the equation:

You can identify that:

Substituting values into the formula and evaluating, you get:
![\begin{gathered} x=\frac{-3\pm\sqrt[]{3^2^{}-4(-10)(-4)}}{2(-10)} \\ \\ x_1=(3)/(20)-(i)/(20)\sqrt[]{151} \\ \\ x_2=(3)/(20)+(i)/(20)\sqrt[]{151} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/e0rw9azgggsil58lbqzpb76q47egavd1fd.png)
Answer
Complex roots:
![\begin{gathered} x_1=(3)/(20)-(i)/(20)\sqrt[]{151} \\ \\ x_2=(3)/(20)+(i)/(20)\sqrt[]{151} \end{gathered}](https://img.qammunity.org/2023/formulas/mathematics/high-school/phv8tbohuxq938xtq9do97km8b1x5f09w7.png)