1 Answer

NVitius · Answer 1 · 2023-12-11T20:12:37+0000

The distance between two points in the plane is:

$d(P,Q)=\sqrt[]{(x_2-x_1)^2+(y_2}-y_1)^2$

The points A and B have coordinates A(5,3) and B(5,6). Then the distance between them is:

$\begin{gathered} d(A,B)=\sqrt[]{(5-5)^2+(6-3)^2} \\ =\sqrt[]{(3)^2} \\ =\sqrt[]{9} \\ =3 \end{gathered}$

Therefore, the length of the side AB is 3 units.

Please log in or register to add a comment.