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How many grams of solute would you use to prepare the following solutions?241.0 mL of 1.11 M NaOHExpress your answer with the appropriate units.

User Lee Mac
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1 Answer

2 votes

Answer:

10.7 grams

Explanations:

The formula for calculating the molarity of a solution is given as:


\begin{gathered} molarity=(moles)/(volume) \\ moles=molarity* volume \end{gathered}

Given the following parameters

molarity of NaOH = 1.11M

volume of solution = 241.0mL = 0.241L

Find the moles of NaOH


\begin{gathered} moles\text{ of Na}OH=(1.11mol)/(L)*0.241L \\ moles\text{ of Na}OH=0.2675moles \end{gathered}

Determine the mass of solute (NaOH)


\begin{gathered} Mass\text{ of NaOH}=mole* molar\text{ mass} \\ Mass\text{ of NaOH}=0.2675*40 \\ Mass\text{ of NaOH}=10.7grams \end{gathered}

Hence the grams of solute that would be used to prepare the solution is 10.7grams

User Erick Willian
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