Question

How many grams of solute would you use to prepare the following solutions?241.0 mL of 1.11 M NaOHExpress your answer with the appropriate units.

Answer 1

10.7 grams

Explanations:

The formula for calculating the molarity of a solution is given as:

`\begin{gathered} molarity=(moles)/(volume) \\ moles=molarity* volume \end{gathered}`

Given the following parameters

molarity of NaOH = 1.11M

volume of solution = 241.0mL = 0.241L

Find the moles of NaOH

`\begin{gathered} moles\text{ of Na}OH=(1.11mol)/(L)*0.241L \\ moles\text{ of Na}OH=0.2675moles \end{gathered}`

Determine the mass of solute (NaOH)

`\begin{gathered} Mass\text{ of NaOH}=mole* molar\text{ mass} \\ Mass\text{ of NaOH}=0.2675*40 \\ Mass\text{ of NaOH}=10.7grams \end{gathered}`

Hence the grams of solute that would be used to prepare the solution is 10.7grams